One mole of an ideal gas undergoes two different cyclic processes I and II, as shown in the π-π diagrams below. In cycle I, processes π, π, π and π are isobaric, isothermal, isobaric and isochoric, respectively. In cycle II, processes π ′ , π ′ , π ′ and π ′ are isothermal, isochoric, isobaric and isochoric, respectively. The total work done during cycle I is ππΌ and that during cycle II is ππΌπΌ. The ratio ππΌ/ππΌπΌ is _______.
To determine the ratio
of the work done during cycle I to that during cycle II, we need to analyze each cycle step-by-step and calculate the work done in each process.
Cycle I:
Process (Isobaric Expansion):
Work done:
Process (Isothermal Compression):
Work done:
Process (Isobaric Compression):
Work done:
Process (Isochoric Process):
Work done: (since volume is constant)
Total Work for Cycle I:
Cycle II:
Process (Isothermal Expansion):
Work done:
Process (Isochoric Process):
Work done: (since volume is constant)
Process (Isobaric Compression):
Work done:
Process (Isochoric Process):
Work done: (since volume is constant)
Total Work for Cycle II:
Ratio :
This ratio depends on the specific values of and . Without numerical values, we cannot simplify this expression further. However, the ratio can be calculated if the specific values of these parameters are provided.
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