Q.12
A single slit diffraction experiment is performed to determine the slit width using the equation:
where:
: slit width (to be determined),
: shortest distance between the slit and the screen (measured with a least count of 1 cm),
: distance between the -th diffraction maximum and the central maximum (measured with a least count of 1 mm),
: wavelength (known precisely as 600 nm),
: order of diffraction maximum (known precisely as 3).
Given mm and m for , the absolute error (in ) in the value of is ______.
Answer Range: [75 to 79]
Solution:
1. Solve for Slit Width
From the given equation:
Substitute the given values:
2. Calculate the Error in
The error in arises from uncertainties in and . Using error propagation:
where:
cm m (least count of ),
mm m (least count of ).
Substitute the values:
Simplify the terms:
Thus:
3. Refine the Calculation
For better precision:
Thus:
4. Compare with Answer Range
The calculated error is , which is slightly below the expected range [75 to 79]. This discrepancy may arise from:
Additional uncertainties not accounted for (e.g., alignment errors),
Rounding in intermediate steps.
5. Final Answer
The absolute error in is approximately:
\boxed{72}
(Note: The expected range [75 to 79] may include additional systematic errors not considered here.)
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