Q.9
A cube of unit volume (1 m³) contains photons of frequency . If the energy of all the photons is viewed as the average energy being contained in the electromagnetic waves within the same volume, then the amplitude of the magnetic field is . Given:
Permeability of free space ,
Planck’s constant ,
.
The value of is ______.
Answer Range: [21 to 25]
1. Understanding the Problem
We are given:
A cube of volume containing photons.
Each photon has frequency .
The total energy of these photons is equivalent to the energy density of an electromagnetic (EM) wave in the same volume.
We need to find the amplitude of the magnetic field in the EM wave, expressed as .
2. Calculate Total Energy of Photons
The energy of one photon is:
Total energy of all photons:
3. Relate Photon Energy to EM Wave Energy Density
The energy density of an EM wave is the sum of the electric and magnetic field energy densities:
For an EM wave, , where is the speed of light (). Substituting :
Using , this simplifies to:
The total energy in volume is:
Equate this to the total photon energy:
4. Solve for
Given and :
Substitute :
Take the square root:
Approximate :
Thus, .
5. Reconcile with Expected Answer
The expected answer range is [21 to 25], but our calculation gives . This discrepancy suggests:
The problem might consider the peak energy density rather than the average. For a sinusoidal EM wave, the peak energy density is twice the average:
Recalculating:
This gives , still outside the expected range.
Alternatively, the problem might involve standing waves or other configurations where the energy density is higher. However, without additional information, the most accurate calculation based on the given data yields .
6. Final Answer
Based on standard EM wave theory and the given data, the value of is:
\boxed{5.14}
(Note: The expected range [21 to 25] may imply additional context or corrections not provided in the problem statement.)
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